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Buoyant force (Archimedes' principle) Formula, SPM Physics

Formula: Fb = ρVg. Not given in the exam, recall it.

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Buoyant force (Archimedes' principle)
Fb = ρVg

Not given in the exam, recall it.

What it is for

Buoyant force (Archimedes' principle) is used in Pressure (SPM Physics Form 5). Keep the SI units in every line of working. Pressure

Symbols and SI units

SymbolMeaningSI unit
Fbbuoyant forceN
ρdensity of fluidkg m⁻³
Vvolume of fluid displaced
ggravitational accelerationm s⁻²

Rearrangements

  • ρ = Fb / (Vg)
  • V = Fb / (ρg)

Worked example

An object displaces V = 2.0 × 10⁻³ m³ of water (ρ = 1000 kg m⁻³, g = 9.81 m s⁻²). Fb = ρVg = 1000 × 2.0 × 10⁻³ × 9.81 = 19.62 N ≈ 19.6 N.

Common trap

Use the density of the fluid, not the object. V is the volume of fluid displaced (the submerged volume).

Understanding buoyant force (Archimedes' principle)

Fb is the buoyant (upthrust) force in newtons (N), ρ (rho) is the density of the fluid in kilograms per cubic metre (kg m⁻³), V is the volume of fluid displaced in cubic metres (m³), and g is the gravitational acceleration in metres per second squared (m s⁻²). Archimedes' principle says the upthrust on an object equals the weight of the fluid it displaces, and ρVg is exactly that weight.

The upthrust acts upward, opposing the object's weight.

Use the density of the fluid, not the object, and take V as the submerged volume, the volume of fluid pushed aside. Rearrange to find the fluid density with ρ = Fb / (Vg) or the displaced volume with V = Fb / (ρg).

A fully submerged object displaces its own whole volume.

A worked example, step by step

A metal block of volume V = 5.0 × 10⁻⁴ m³ is fully submerged in water of density ρ = 1000 kg m⁻³ (take g = 9.81 m s⁻²). Find the buoyant force on it.

  1. Write the formula: Fb = ρVg.
  2. Substitute with units: Fb = 1000 kg m⁻³ × 5.0 × 10⁻⁴ m³ × 9.81 m s⁻² = 4.905 N.
  3. Round: Fb = 4.9 N to two significant figures.

The unit check gives kg m⁻³ × m³ × m s⁻² = kg m s⁻² = N. Because the block is fully submerged, V is its entire volume. If the same block floated, only the submerged part would count, and the upthrust would equal the block's weight.

Common mistakes and how this is tested

The key trap is using the object's density instead of the fluid's, the upthrust depends on the fluid displaced, so ρ is always the fluid density. Another is using the whole object volume when the object only floats partly submerged; then V is just the submerged volume.

  • Forgetting the answer is a force in newtons.
  • Confusing the upthrust with the object's weight.

Questions ask you to calculate the buoyant force, explain why a ship floats or a submerged object feels lighter, or state Archimedes' principle. For the statement, say the buoyant force equals the weight of fluid displaced.

To decide floating or sinking, compare the upthrust with the object's weight.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English), Sijil Pelajaran Malaysia: Format Pentaksiran mulai 2021, Fizik (4531) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Written by the spmphysics.com.my editorial team.· Updated 5 Sept 2026

Frequently asked questions

Is this formula given in the exam?
No. SPM Physics papers provide no formula sheet, so this must be recalled.
Why does an object feel lighter in water?
The water exerts an upward buoyant force Fb = ρVg that opposes gravity. The apparent weight is the real weight minus this upthrust, so the object feels lighter.
Which density do I use in Fb = ρVg?
The density of the fluid, not the object. The upthrust equals the weight of fluid displaced, so it depends on how dense the surrounding fluid is.
When does an object float rather than sink?
It floats when the maximum upthrust (with the object fully submerged) is at least equal to its weight. Then it settles so the submerged volume displaces fluid weighing exactly its own weight.

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