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Boyle's law Formula, SPM Physics

Formula: p₁V₁ = p₂V₂. Not given in the exam, recall it.

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Boyle's law
p₁V₁ = p₂V₂

Not given in the exam, recall it.

What it is for

Boyle's law is used in Heat (SPM Physics Form 4). Keep the SI units in every line of working. Heat

Symbols and SI units

SymbolMeaningSI unit
p₁initial pressurePa
V₁initial volume
p₂final pressurePa
V₂final volume

Rearrangements

  • p₂ = p₁V₁ / V₂
  • V₂ = p₁V₁ / p₂

Worked example

Gas at p₁ = 100 kPa, V₁ = 500 cm³ is compressed to V₂ = 200 cm³ at constant temperature. p₂ = p₁V₁ / V₂ = (100 × 500) / 200 = 250 kPa.

Common trap

Valid only at constant temperature for a fixed mass of gas. Pressure and volume are inversely proportional.

Understanding Boyle's law

Boyle's law p₁V₁ = p₂V₂ applies to a fixed mass of gas at constant temperature. p is pressure and V is volume, with subscripts 1 and 2 for the initial and final states. Pressure may be in pascals (Pa) or kilopascals (kPa), and volume in m³, litres or cm³, as long as both sides match.

The law says pressure and volume are inversely proportional: squeeze a gas into half the volume and its pressure doubles. This happens because the particles hit the walls more often in a smaller space.

To find an unknown, rearrange to p₂ = p₁V₁ / V₂ or V₂ = p₁V₁ / p₂. Temperature is not in the formula because it is held constant.

A worked example, step by step

A gas at p₁ = 200 kPa occupies V₁ = 250 cm³. It expands to V₂ = 500 cm³ at constant temperature.

Find the new pressure p₂.

Write the rearranged formula: p₂ = p₁V₁ / V₂. Substitute with units: p₂ = (200 kPa × 250 cm³) / 500 cm³.

Top line: 200 × 250 = 50000. Divide by 500: 50000 / 500 = 100.

So p₂ = 100 kPa. The cm³ units cancel, leaving kPa.

Doubling the volume has halved the pressure, exactly as the inverse relationship predicts. The answer is 100 kPa, or 1.0 × 10² kPa to two significant figures.

Common mistakes and how this is tested

The key condition is that temperature and the mass of gas stay constant. If the temperature changes, use the general gas law instead.

Because it is a ratio, volume units need not be m³, but they must match on both sides.

Other errors: expecting pressure to rise when volume rises (it falls); mixing kPa with Pa across the equation; and swapping the initial and final labels so the ratio inverts.

Under calculate, show the substitution with matching units. Explain may ask why the pressure changes in terms of particle collisions, and a graph question may ask you to recognise a p against 1/V straight line.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English), Sijil Pelajaran Malaysia: Format Pentaksiran mulai 2021, Fizik (4531) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Written by the spmphysics.com.my editorial team.· Updated 5 Sept 2026

Frequently asked questions

Is this formula given in the exam?
No. SPM Physics papers provide no formula sheet, so this must be recalled.
Do I need SI units for Boyle's law?
No. Since it is a ratio p₁V₁ = p₂V₂, any consistent units work. Use the same pressure unit on both sides and the same volume unit on both sides, and the answer keeps that unit.
What must stay constant for Boyle's law to hold?
The temperature and the mass (amount) of gas must both be constant. Only then are pressure and volume inversely proportional. If temperature changes, use the general gas law.
What graph shows Boyle's law as a straight line?
A graph of pressure p against the reciprocal of volume 1/V gives a straight line through the origin. A graph of p against V instead gives a curve, because they are inversely proportional.

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