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Electromotive force, Meaning (SPM Physics)

The energy supplied by a source to move one coulomb of charge around a complete circuit; measured in volts (V).

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EnglishElectromotive force
Bahasa MelayuDaya gerak elektrik
中文电动势

Definition

The energy supplied by a source to move one coulomb of charge around a complete circuit; measured in volts (V).

Electricity

In exam terms

Electromotive force (emf), symbol ε, is the energy supplied by a source to drive one coulomb of charge around a complete circuit. It is defined as ε = E/Q and is measured in volts (V), where 1 V = 1 J C⁻¹.

Despite its name, emf is not a force; it is an energy-per-charge quantity. It equals the terminal potential difference only when no current is drawn (open circuit).

Example of correct use: a cell that supplies 6 J of energy to move 2 C of charge has an emf of ε = E/Q = 6 J ÷ 2 C = 3 V.

Do not confuse it with…

Do not confuse emf with terminal potential difference. The emf is the total energy per coulomb given by the source; the terminal p.d. is the energy per coulomb delivered to the external circuit.

Because of internal resistance, V = ε − Ir, so the terminal p.d. is always less than the emf when current flows.

In Paper 2, if asked to define emf you must refer to the energy supplied per unit charge (per coulomb) for a full circuit, not just say “voltage of the battery”.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Frequently asked questions

Is emf really a force?
No. Despite the name, emf is an energy per unit charge, measured in volts, not in newtons. It describes how much energy a source gives to each coulomb of charge.
How is emf different from terminal potential difference?
Emf is the total energy supplied per coulomb; terminal p.d. is the energy delivered to the external circuit. They are equal only when no current flows.
How do you measure the emf of a cell?
Connect a high-resistance voltmeter across the cell when it is not driving any current (open circuit), so no potential drops across the internal resistance.

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