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Linear magnification, Meaning (SPM Physics)

The ratio of the height of the image to the height of the object, equal to image distance divided by object distance.

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EnglishLinear magnification
Bahasa MelayuPembesaran linear
中文线性放大率

Definition

The ratio of the height of the image to the height of the object, equal to image distance divided by object distance.

Light and Optics

In exam terms

Linear magnification m is the ratio of the height of the image to the height of the object: m = image height ÷ object height. For a thin lens it equals the image distance divided by the object distance, m = v ÷ u.

It has no unit because it is a ratio.

If m is greater than 1 the image is enlarged; if less than 1 it is diminished; if equal to 1 it is the same size. For example, if v = 20 cm and u = 10 cm, then m = 20 ÷ 10 = 2, so the image is twice the object's height.

Do not confuse it with power of a lens

Do not confuse linear magnification with the power of a lens. Magnification describes how big the image is compared with the object; power (1 ÷ focal length, in dioptres) describes how strongly the lens bends light.

A lens has fixed power but the magnification changes with object distance.

In Paper 2, a calculate the magnification question expects m = v ÷ u (or image height ÷ object height), and you should also state whether the image is larger or smaller than the object.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Frequently asked questions

Why does linear magnification have no unit?
It is a ratio of two lengths (image height to object height), so the length units cancel, leaving a pure number.
What does m = 1 mean?
The image is exactly the same size as the object. This happens when the object is placed at twice the focal length of a converging lens.
Can I use m = v ÷ u and m = image height ÷ object height together?
Yes. Both give the same magnification, so you can use one to find an unknown height or distance from the other.

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