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Electricity Calculations (Medium), SPM Physics

The Medium calculation set for Electricity. Use the same method every time and show every line of working.

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How to approach

These need a rearrangement or two steps, often finding one quantity before the one asked for.

The method

  1. List what is given, with units.
  2. Choose the formula and rearrange for the unknown.
  3. Substitute with units on every line.
  4. Round to the correct significant figures.

Worked examples

Electric charge
Q = It
A current I = 2.0 A flows for t = 30 s. Q = It = 2.0 × 30 = 60 C.
Potential difference
V = W / Q
W = 60 J of energy is transferred by Q = 10 C of charge. V = W / Q = 60 / 10 = 6.0 V.
Ohm's law
V = IR (R = V / I)
A current I = 3.0 A flows through a resistor R = 4.0 Ω. V = IR = 3.0 × 4.0 = 12 V.
Resistors in series
R = R₁ + R₂ + …
Two resistors R₁ = 3 Ω and R₂ = 5 Ω are in series. R = R₁ + R₂ = 3 + 5 = 8 Ω.
Resistors in parallel
1/R = 1/R₁ + 1/R₂ + …
Two resistors R₁ = 6 Ω and R₂ = 3 Ω are in parallel. 1/R = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2, so R = 2 Ω.
Electromotive force
ε = IR + Ir = V + Ir
A cell of ε = 1.5 V and r = 1.0 Ω drives a current I = 0.5 A. V = ε − Ir = 1.5 − (0.5 × 1.0) = 1.0 V (terminal p.d.).
Electrical energy
E = VIt
A device runs at V = 12 V and I = 2.0 A for t = 60 s. E = VIt = 12 × 2.0 × 60 = 1440 J.
Electrical power
P = VI = I²R = V²/R
An appliance draws I = 5.0 A at V = 240 V. P = VI = 240 × 5.0 = 1200 W = 1.2 kW.

Where marks are lost

Skipping units, rounding too early, and writing only the final answer (which loses method marks in Paper 2).

Practise these

Try each formula above with your own numbers, showing every line. Bring anything you get stuck on to a one-to-one lesson.

Formulas you use for Electricity calculations

These mid-level problems draw on the 8 relationships in Electricity. None is printed in the exam, so recall each and write its symbols with units before substituting:

  • Q = It, Electric charge
  • V = W / Q, Potential difference
  • V = IR (R = V / I), Ohm's law
  • R = R₁ + R₂ + …, Resistors in series
  • 1/R = 1/R₁ + 1/R₂ + …, Resistors in parallel
  • ε = IR + Ir = V + Ir, Electromotive force
  • E = VIt, Electrical energy
  • P = VI = I²R = V²/R, Electrical power

A worked example, with units on every line

Using 1/R = 1/R₁ + 1/R₂ + … (R = total resistance (Ω); R₁ = first resistance (Ω); R₂ = second resistance (Ω)):

Two resistors R₁ = 6 Ω and R₂ = 3 Ω are in parallel.
1/R = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2, so R = 2 Ω.

Where the marks are, and the common mistakes

In Paper 2, calculation marks are awarded line by line: the formula, the substitution with units, and the final answer with its unit and sensible significant figures. Watch this trap: Take the reciprocal at the end to get R (not 1/R).

The total is smaller than the smallest resistor. For mid-level items, expect one rearrangement and a unit conversion.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Written by the spmphysics.com.my editorial team.· Updated 5 Sept 2026

Frequently asked questions

Are formulas given in the exam?
No. You must recall SPM Physics formulas.
Is a formula sheet given for these calculations?
No. SPM Physics (4531) provides no formula sheet, recall each formula and write units on every line.
What does the medium band mean?
Mid-level items usually need one rearrangement and a unit conversion.
Can a tutor mark my working?
Yes, in a one-to-one lesson the teacher checks each line and fixes the exact step that loses marks. From RM50/hr, paid trial available.

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