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Pressure Calculations (KBAT / Higher-Order), SPM Physics

The KBAT / Higher-Order calculation set for Pressure. Use the same method every time and show every line of working.

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How to approach

Higher-order questions apply the formula to a described situation and ask you to explain or justify. Structure your answer: state, calculate, then interpret.

The method

  1. List what is given, with units.
  2. Choose the formula and rearrange for the unknown.
  3. Substitute with units on every line.
  4. Round to the correct significant figures.

Worked examples

Pressure
P = F / A
A force F = 200 N acts over an area A = 0.5 m². P = F / A = 200 / 0.5 = 400 Pa.
Pressure in a liquid column
P = hρg
Find the pressure at depth h = 2.0 m in water (ρ = 1000 kg m⁻³, g = 9.81 m s⁻²). P = hρg = 2.0 × 1000 × 9.81 = 19620 Pa ≈ 1.96 × 10⁴ Pa.
Pascal's principle
F₁ / A₁ = F₂ / A₂
A hydraulic system: F₁ = 20 N on A₁ = 0.01 m² acts on a piston of A₂ = 0.05 m². F₂ = F₁ × A₂ / A₁ = 20 × (0.05 / 0.01) = 100 N.
Buoyant force (Archimedes' principle)
Fb = ρVg
An object displaces V = 2.0 × 10⁻³ m³ of water (ρ = 1000 kg m⁻³, g = 9.81 m s⁻²). Fb = ρVg = 1000 × 2.0 × 10⁻³ × 9.81 = 19.62 N ≈ 19.6 N.

Where marks are lost

Skipping units, rounding too early, and writing only the final answer (which loses method marks in Paper 2).

Practise these

Try each formula above with your own numbers, showing every line. Bring anything you get stuck on to a one-to-one lesson.

Formulas you use for Pressure calculations

These higher-order (KBAT) problems draw on the 4 relationships in Pressure. None is printed in the exam, so recall each and write its symbols with units before substituting:

  • P = F / A, Pressure
  • P = hρg, Pressure in a liquid column
  • F₁ / A₁ = F₂ / A₂, Pascal's principle
  • Fb = ρVg, Buoyant force (Archimedes' principle)

A worked example, with units on every line

Using Fb = ρVg (Fb = buoyant force (N); ρ = density of fluid (kg m⁻³); V = volume of fluid displaced (m³); g = gravitational acceleration (m s⁻²)):

An object displaces V = 2.0 × 10⁻³ m³ of water (ρ = 1000 kg m⁻³, g = 9.81 m s⁻²).
Fb = ρVg = 1000 × 2.0 × 10⁻³ × 9.81 = 19.62 N ≈ 19.6 N.

Where the marks are, and the common mistakes

In Paper 2, calculation marks are awarded line by line: the formula, the substitution with units, and the final answer with its unit and sensible significant figures. Watch this trap: Use the density of the fluid, not the object.

V is the volume of fluid displaced (the submerged volume). For higher-order (KBAT) items, expect multi-step problems that combine two relationships or ask you to rearrange before substituting.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Written by the spmphysics.com.my editorial team.· Updated 5 Sept 2026

Frequently asked questions

Are formulas given in the exam?
No. You must recall SPM Physics formulas.
Is a formula sheet given for these calculations?
No. SPM Physics (4531) provides no formula sheet, recall each formula and write units on every line.
What does the kbat band mean?
Higher-order (KBAT) items combine ideas or need rearranging before you substitute.
Can a tutor mark my working?
Yes, in a one-to-one lesson the teacher checks each line and fixes the exact step that loses marks. From RM50/hr, paid trial available.

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