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Charles's law Formula, SPM Physics

Formula: V₁ / T₁ = V₂ / T₂. Not given in the exam, recall it.

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Charles's law
V₁ / T₁ = V₂ / T₂

Not given in the exam, recall it.

What it is for

Charles's law is used in Heat (SPM Physics Form 4). Keep the SI units in every line of working. Heat

Symbols and SI units

SymbolMeaningSI unit
V₁initial volume
T₁initial absolute temperatureK
V₂final volume
T₂final absolute temperatureK

Rearrangements

  • V₂ = V₁T₂ / T₁
  • T₂ = V₂T₁ / V₁

Worked example

Gas of volume V₁ = 300 cm³ at T₁ = 300 K is heated to T₂ = 400 K at constant pressure. V₂ = V₁T₂ / T₁ = (300 × 400) / 300 = 400 cm³.

Common trap

Temperature must be in kelvin. Valid only at constant pressure for a fixed mass of gas.

Understanding Charles's law

Charles's law V₁ / T₁ = V₂ / T₂ applies to a fixed mass of gas at constant pressure. V is volume, which may be in m³, litres or cm³, and T is the absolute temperature in kelvin (K). The subscripts 1 and 2 mark the initial and final states.

The law says volume is directly proportional to absolute temperature: heat a gas and it expands in step with its kelvin temperature. This is because hotter particles move faster and push the walls out to keep pressure steady.

To find an unknown, rearrange to V₂ = V₁T₂ / T₁ or T₂ = V₂T₁ / V₁. Temperature must be in kelvin, so convert any Celsius value first.

A worked example, step by step

A gas of volume V₁ = 400 cm³ is at θ₁ = 27 °C. It is heated at constant pressure to θ₂ = 177 °C. Find the new volume V₂.

Convert to kelvin first: T₁ = 27 + 273 = 300 K, T₂ = 177 + 273 = 450 K.

Write the rearranged formula: V₂ = V₁T₂ / T₁. Substitute with units: V₂ = (400 cm³ × 450 K) / 300 K.

Top line: 400 × 450 = 180000. Divide by 300: 180000 / 300 = 600.

So V₂ = 600 cm³. The kelvin units cancel, leaving cm³.

The gas expands to 600 cm³, quoted to three significant figures.

Common mistakes and how this is tested

The biggest trap is leaving temperature in Celsius. If you used 27 and 177 directly the ratio would be wrong; you must convert to 300 K and 450 K first.

The law also holds only at constant pressure for a fixed mass of gas.

Other errors: assuming volume doubles when Celsius temperature doubles (it does not); mixing volume units across the equation; and forgetting that a gas contracts when cooled, so V₂ can be smaller than V₁.

Under calculate, show the kelvin conversion and the substitution with units. Explain may ask why a balloon expands in the sun, using particle motion.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English), Sijil Pelajaran Malaysia: Format Pentaksiran mulai 2021, Fizik (4531) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Written by the spmphysics.com.my editorial team.· Updated 5 Sept 2026

Frequently asked questions

Is this formula given in the exam?
No. SPM Physics papers provide no formula sheet, so this must be recalled.
Why convert temperature to kelvin for Charles's law?
Volume is proportional to absolute temperature, measured from absolute zero. Celsius has an arbitrary zero, so using it gives wrong ratios. Convert with T = °C + 273 before substituting.
What condition must hold for Charles's law?
The pressure and the mass of gas must stay constant. Only then is volume directly proportional to absolute temperature. If pressure changes too, use the general gas law.
Does doubling the Celsius temperature double the volume?
No. Only doubling the absolute (kelvin) temperature doubles the volume. Going from 27 °C to 54 °C is 300 K to 327 K, so the volume rises by just a small factor, not double.

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