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Kepler's third law Formula, SPM Physics

Formula: T² ∝ r³ (T²/r³ = constant). Not given in the exam, recall it.

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Kepler's third law
T² ∝ r³ (T²/r³ = constant)

Not given in the exam, recall it.

What it is for

Kepler's third law is used in Gravitation (SPM Physics Form 4). Keep the SI units in every line of working. Gravitation

Symbols and SI units

SymbolMeaningSI unit
Torbital periods
rorbital radiusm

Rearrangements

  • T₁²/r₁³ = T₂²/r₂³
  • T² = (constant) × r³
  • r³ = T² / (constant)

Worked example

Planet A has period T₁ = 1 yr at radius r₁; planet B orbits at r₂ = 4r₁. T₂² / r₂³ = T₁² / r₁³ → T₂² = T₁² (r₂/r₁)³ = 1² × 4³ = 64, so T₂ = 8 yr.

Common trap

Square the period and cube the radius. Use the ratio form T₁²/r₁³ = T₂²/r₂³ to compare two orbits; keep units consistent on both sides.

Understanding Kepler's third law

Kepler’s third law says the square of a planet’s orbital period is proportional to the cube of its orbital radius: T² ∝ r³, so T² / r³ = constant for every body orbiting the same central mass.

Here T is the orbital period in seconds (s) and r is the orbital radius in metres (m). Because the ratio T²/r³ is fixed, two orbits around the same star or planet can be compared directly.

The most useful form is the ratio T₁²/r₁³ = T₂²/r₂³. To find an unknown period, rearrange to T₂² = T₁² (r₂/r₁)³; to find a radius, use r³ = T² / (constant).

Keep the same units on both sides.

A worked example, step by step

Planet A orbits a star with period T₁ = 2 years at radius r₁. Planet B orbits the same star at r₂ = 9r₁.

Find the period of planet B.

Use the ratio form and substitute:

T₂² / r₂³ = T₁² / r₁³, so T₂² = T₁² (r₂/r₁)³ = 2² × 9³

T₂² = 4 × 729 = 2916, so T₂ = √2916 = 54 years.

Because the radius is 9 times larger, the period grows by a factor of √(9³) = 27, giving 54 years. The ratio method avoids needing the value of the constant, and it works as long as both planets orbit the same central body.

The answer keeps two significant figures.

Common mistakes and how this is tested

The core rule is to square the period and cube the radius; swapping the powers (cubing T or squaring r) is the most frequent error.

Other slips: forgetting to cube the radius ratio when using T₂² = T₁²(r₂/r₁)³; taking the square root of only one side; and mixing units (using years on one side and seconds on the other). The law also only compares bodies orbiting the same central mass.

It appears under state (write the law), calculate (find an unknown period or radius from another orbit), and explain (why outer planets take much longer to orbit than inner ones).

Source: DSKP KSSM Physics Form 4 and 5 (Versi English), Sijil Pelajaran Malaysia: Format Pentaksiran mulai 2021, Fizik (4531) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Written by the spmphysics.com.my editorial team.· Updated 5 Sept 2026

Frequently asked questions

Is this formula given in the exam?
No. SPM Physics papers provide no formula sheet, so this must be recalled.
Why does the ratio method avoid the constant?
Because T²/r³ is the same for both orbits around the same central mass, you can set T₁²/r₁³ = T₂²/r₂³ and cancel the constant. You only need the ratio of the radii, not its actual value.
What units should T and r be in?
Any consistent units work, as long as both sides of T₁²/r₁³ = T₂²/r₂³ use the same ones. If you keep periods in years and radii as a ratio, the answer comes out in years.
Why do outer planets take longer to orbit?
Because T² is proportional to r³, a larger orbital radius means a much larger period. Increasing r by a factor of 4 raises T by a factor of 8, so distant planets orbit far more slowly.

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