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Pressure law Formula, SPM Physics

Formula: p₁ / T₁ = p₂ / T₂. Not given in the exam, recall it.

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Pressure law
p₁ / T₁ = p₂ / T₂

Not given in the exam, recall it.

What it is for

Pressure law is used in Heat (SPM Physics Form 4). Keep the SI units in every line of working. Heat

Symbols and SI units

SymbolMeaningSI unit
p₁initial pressurePa
T₁initial absolute temperatureK
p₂final pressurePa
T₂final absolute temperatureK

Rearrangements

  • p₂ = p₁T₂ / T₁
  • T₂ = p₂T₁ / p₁

Worked example

Gas at p₁ = 100 kPa, T₁ = 300 K is heated to T₂ = 450 K at constant volume. p₂ = p₁T₂ / T₁ = (100 × 450) / 300 = 150 kPa.

Common trap

Temperature must be in kelvin. Valid only at constant volume for a fixed mass of gas.

Understanding the pressure law

The pressure law links the pressure and absolute temperature of a fixed mass of gas held at constant volume. p₁ is the initial pressure and p₂ the final pressure, both in pascals (Pa). T₁ and T₂ are the initial and final absolute temperatures in kelvin (K).

When a gas is heated at constant volume its molecules move faster and strike the walls harder and more often, so the pressure rises in direct proportion to the absolute temperature. This is why p/T stays constant, giving p₁/T₁ = p₂/T₂.

To make one quantity the subject, cross-multiply first. For the new pressure use p₂ = p₁T₂ / T₁; for the new temperature use T₂ = p₂T₁ / p₁.

Always convert Celsius to kelvin before substituting.

A worked example, step by step

A sealed steel can holds gas at p₁ = 120 kPa and T₁ = 27 °C. It is cooled to T₂ = −23 °C with the volume unchanged.

Find the new pressure.

First convert to kelvin: T₁ = 27 + 273 = 300 K and T₂ = −23 + 273 = 250 K.

Write the formula, then substitute with units:

p₂ = p₁T₂ / T₁ = (120 kPa × 250 K) / 300 K = 100 kPa.

The kelvin units cancel, leaving the answer in kilopascals: p₂ = 100 kPa (3 significant figures). Cooling lowers the pressure, which matches our expectation because pressure falls with absolute temperature at constant volume.

Common mistakes and how this is tested

The most common error is using Celsius instead of kelvin. The law only works with absolute temperature, so convert every temperature with K = °C + 273 before you divide.

Other frequent slips: forgetting the volume must stay constant (the law fails if the gas expands or is compressed); mixing up which pressure pairs with which temperature (p₁ goes with T₁); and rounding the kelvin conversion too early.

Under calculate you must show the formula, the kelvin substitution and the final unit. Under explain you may be asked why pressure rises with temperature at constant volume, so link it to faster molecules and harder, more frequent collisions.

Under define, state the proportional relationship in words.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English), Sijil Pelajaran Malaysia: Format Pentaksiran mulai 2021, Fizik (4531) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Written by the spmphysics.com.my editorial team.· Updated 5 Sept 2026

Frequently asked questions

Is this formula given in the exam?
No. SPM Physics papers provide no formula sheet, so this must be recalled.
Why must temperature be in kelvin for the pressure law?
Because pressure is proportional to absolute temperature, not Celsius. At 0 °C a gas still has pressure, but 0 °C is not zero on the pressure scale. Kelvin starts at absolute zero, so p/T is only constant when T is measured in kelvin. Convert with K = °C + 273.
What condition must be kept constant?
The volume and the mass of gas. The pressure law p₁/T₁ = p₂/T₂ applies to a fixed mass of gas in a rigid, sealed container so the volume cannot change. If the gas can expand, use the general gas law p₁V₁/T₁ = p₂V₂/T₂ instead.
Can I leave pressure in kPa instead of Pa?
Yes, as long as both pressures use the same unit. The formula is a ratio, so the pressure units cancel. You may keep p₁ and p₂ both in kPa, both in Pa or both in atm; only the temperatures must be converted to kelvin.

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