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Refractive index (Snell's law) Formula, SPM Physics

Formula: n = sin i / sin r. Not given in the exam, recall it.

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Refractive index (Snell's law)
n = sin i / sin r

Not given in the exam, recall it.

What it is for

Refractive index (Snell's law) is used in Light and Optics (SPM Physics Form 4). Keep the SI units in every line of working. Light and Optics

Symbols and SI units

SymbolMeaningSI unit
nrefractive index (no unit, ratio),
iangle of incidence°
rangle of refraction°

Rearrangements

  • sin i = n sin r
  • sin r = sin i / n

Worked example

Light enters glass with i = 60° and r = 35°. n = sin i / sin r = sin 60° / sin 35° = 0.866 / 0.574 = 1.51.

Common trap

Angles are measured from the normal, not the surface. The angle in the less dense medium (usually air) is i.

Understanding Snell’s law

Snell’s law, n = sin i / sin r, gives the refractive index of a medium from the angles a ray makes as it crosses a boundary. n is the refractive index, a pure ratio with no unit. i is the angle of incidence and r is the angle of refraction, both measured in degrees (°) from the normal, the line perpendicular to the surface.

A denser optical medium bends light more, giving a larger n. Because the ray bends towards the normal on entering a denser medium, r is smaller than i there, so sin i / sin r is greater than 1.

Rearrange to find an angle: sin i = n sin r or sin r = sin i / n. Take the inverse sine at the end to recover the angle itself.

A worked example, step by step

A ray of light travels from air into water of refractive index n = 1.33, striking the surface at an angle of incidence i = 45°. Find the angle of refraction r.

Rearrange Snell’s law to make sin r the subject:

sin r = sin i / n = sin 45° / 1.33 = 0.707 / 1.33 = 0.532.

Take the inverse sine:

r = sin⁻¹(0.532) = 32.1°.

So r = 32.1° (3 significant figures). The refracted angle is smaller than the incident angle, which is correct because light bends towards the normal when entering a denser medium.

Common mistakes and how this is tested

The most common trap is measuring the angles from the surface instead of from the normal. Both i and r are always measured from the normal, so an angle quoted "from the surface" must be subtracted from 90° first.

Other errors: forgetting to take the inverse sine, so leaving the answer as sin r rather than r; putting the calculator in radian mode instead of degrees; and swapping i and r, which inverts n.

Under calculate show n = sin i / sin r, substitute the angles and give n to a sensible number of figures. Under define you may be asked to state Snell’s law or define refractive index.

Under explain, relate a larger n to greater bending.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English), Sijil Pelajaran Malaysia: Format Pentaksiran mulai 2021, Fizik (4531) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Written by the spmphysics.com.my editorial team.· Updated 5 Sept 2026

Frequently asked questions

Is this formula given in the exam?
No. SPM Physics papers provide no formula sheet, so this must be recalled.
Are the angles measured from the surface or the normal?
Always from the normal, the line drawn perpendicular to the surface at the point where the ray hits. If a question gives an angle from the surface, subtract it from 90° before using Snell’s law. Measuring from the wrong reference is the single biggest source of lost marks here.
Why does refractive index have no unit?
Because it is a ratio of two sines, and sines have no units, n is a pure number. A refractive index of 1.33 means light bends by an amount set by that ratio; it is not measured in any physical unit like metres or seconds.
What does a larger refractive index tell me?
A larger n means the medium is optically denser and bends light more strongly towards the normal. Water has n ≈ 1.33 and glass n ≈ 1.5, so glass bends a ray more than water does for the same angle of incidence.

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