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Specific latent heat Formula, SPM Physics

Formula: Q = mL. Not given in the exam, recall it.

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Specific latent heat
Q = mL

Not given in the exam, recall it.

What it is for

Specific latent heat is used in Heat (SPM Physics Form 4). Keep the SI units in every line of working. Heat

Symbols and SI units

SymbolMeaningSI unit
Qheat energyJ
mmasskg
Lspecific latent heatJ kg⁻¹

Rearrangements

  • L = Q / m
  • m = Q / L

Worked example

Find the heat to melt m = 0.5 kg of ice (L = 3.34 × 10⁵ J kg⁻¹). Q = mL = 0.5 × 3.34 × 10⁵ = 1.67 × 10⁵ J.

Common trap

During a change of state the temperature stays constant, so there is no θ term. Use the correct L (fusion for melting, vaporisation for boiling).

Understanding specific latent heat

The equation Q = mL gives the heat needed to change the state of a substance without changing its temperature. Q is heat energy in joules (J), m is mass in kilograms (kg), and L is the specific latent heat in J kg⁻¹.

Specific latent heat is the energy needed to change the state of 1 kg of a substance at constant temperature. This energy goes into breaking or forming the bonds between particles, which is why the temperature stays fixed and there is no θ term.

To find other quantities, rearrange to L = Q / m or m = Q / L. Use latent heat of fusion for melting and freezing, and latent heat of vaporisation for boiling and condensing.

A worked example, step by step

How much heat turns m = 0.2 kg of water at 100 °C completely into steam? The specific latent heat of vaporisation of water is L = 2.26 × 10⁶ J kg⁻¹.

Write the formula: Q = mL. Substitute with units: Q = 0.2 kg × 2.26 × 10⁶ J kg⁻¹.

Multiply: 0.2 × 2.26 × 10⁶ = 0.452 × 10⁶.

So Q = 4.52 × 10⁵ J. The units kg × J kg⁻¹ cancel to J, as required. Vaporising the water needs 4.52 × 10⁵ J, quoted to three significant figures.

Notice this is far more than heating the same water by a few degrees.

Common mistakes and how this is tested

The core trap is that temperature stays constant during a state change, so never include a θ term. Also choose the correct L: fusion for solid-liquid, vaporisation for liquid-gas.

More errors: using grams instead of kilograms for m; adding mcθ energy during the flat part of a heating curve, where only mL applies; and forgetting that the same L applies to the reverse change (freezing releases the fusion energy).

Under calculate, show the substitution with units. Define may ask for the meaning of specific latent heat of vaporisation, and explain may ask why steam causes worse burns than boiling water at the same temperature.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English), Sijil Pelajaran Malaysia: Format Pentaksiran mulai 2021, Fizik (4531) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Written by the spmphysics.com.my editorial team.· Updated 5 Sept 2026

Frequently asked questions

Is this formula given in the exam?
No. SPM Physics papers provide no formula sheet, so this must be recalled.
Why is there no temperature term in Q = mL?
During melting or boiling the temperature stays constant while the state changes. The energy breaks particle bonds rather than raising temperature, so θ = 0 and only mL is needed.
Why is latent heat of vaporisation larger than fusion?
Boiling must separate particles completely into a gas, which needs far more energy than just loosening a solid into a liquid. For water, vaporisation (2.26 × 10⁶ J kg⁻¹) is much larger than fusion (3.34 × 10⁵ J kg⁻¹).
How do I handle a problem with both heating and a state change?
Split it into stages. Use Q = mcθ for the parts where temperature rises, and Q = mL for each flat state-change part, then add the energies together.

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