Back to top

General gas law Formula, SPM Physics

Formula: p₁V₁ / T₁ = p₂V₂ / T₂. Not given in the exam, recall it.

  • Specialist SPM Physics tutoring
  • 5,000+ students helped
  • Experienced Physics teachers
  • Fully online 1-to-1, nationwide
  • Real 1-hour paid trial, from RM50/hr
  • Built on the official SPM syllabus
General gas law
p₁V₁ / T₁ = p₂V₂ / T₂

Not given in the exam, recall it.

What it is for

General gas law is used in Heat (SPM Physics Form 4). Keep the SI units in every line of working. Heat

Symbols and SI units

SymbolMeaningSI unit
p₁initial pressurePa
V₁initial volume
T₁initial absolute temperatureK
p₂final pressurePa
V₂final volume
T₂final absolute temperatureK

Rearrangements

  • V₂ = p₁V₁T₂ / (T₁p₂)
  • p₂ = p₁V₁T₂ / (T₁V₂)
  • T₂ = p₂V₂T₁ / (p₁V₁)

Worked example

Gas at p₁ = 1.0 × 10⁵ Pa, V₁ = 2.0 L, T₁ = 300 K is changed to p₂ = 2.0 × 10⁵ Pa, T₂ = 600 K. V₂ = p₁V₁T₂ / (T₁p₂) = (1.0 × 10⁵ × 2.0 × 600) / (300 × 2.0 × 10⁵) = 2.0 L.

Common trap

Temperature must be in kelvin (K = °C + 273). Volume may be in any unit as long as both sides match.

Understanding the general gas law

The general gas law p₁V₁ / T₁ = p₂V₂ / T₂ connects two states of a fixed mass of gas. p is pressure in pascals (Pa), V is volume in cubic metres (m³) or any consistent unit, and T is the absolute temperature in kelvin (K). The subscripts 1 and 2 mark the initial and final states.

It combines Boyle's, Charles's and the pressure law into one relation, since the quantity pV/T stays constant for a fixed amount of gas. To find one unknown, rearrange, for example V₂ = p₁V₁T₂ / (T₁p₂), p₂ = p₁V₁T₂ / (T₁V₂), or T₂ = p₂V₂T₁ / (p₁V₁).

Temperature must always be in kelvin.

A worked example, step by step

A gas at p₁ = 1.5 × 10⁵ Pa, V₁ = 3.0 L and T₁ = 300 K is compressed to V₂ = 1.5 L and warmed to T₂ = 350 K. Find the new pressure p₂.

Write the rearranged formula: p₂ = p₁V₁T₂ / (T₁V₂). Substitute with units: p₂ = (1.5 × 10⁵ Pa × 3.0 L × 350 K) / (300 K × 1.5 L).

Top line: 1.5 × 10⁵ × 3.0 × 350 = 1.575 × 10⁸. Bottom line: 300 × 1.5 = 450.

Divide: p₂ = 1.575 × 10⁸ / 450 = 3.5 × 10⁵ Pa. The litres cancel, leaving pascals.

The pressure rises to 3.5 × 10⁵ Pa, quoted to two significant figures.

Common mistakes and how this is tested

The biggest trap is leaving temperature in degrees Celsius. Always convert with K = °C + 273 before substituting.

Volume, by contrast, can stay in litres or cm³ as long as both sides use the same unit.

Other errors: mixing pressure units (Pa on one side, kPa on the other); swapping which state is 1 and which is 2; and applying the law to a changing mass of gas, which it does not allow.

Under calculate, show the substitution with units and the kelvin conversion. Explain may ask why a sealed can bursts when heated, or why a gas cools as it expands.

Source: DSKP KSSM Physics Form 4 and 5 (Versi English), Sijil Pelajaran Malaysia: Format Pentaksiran mulai 2021, Fizik (4531) (Bahagian Pembangunan Kurikulum (BPK), KPM)

Written by the spmphysics.com.my editorial team.· Updated 5 Sept 2026

Frequently asked questions

Is this formula given in the exam?
No. SPM Physics papers provide no formula sheet, so this must be recalled.
Do I have to convert volume to cubic metres?
No. Volume can stay in litres or cm³ provided both sides of the equation use the same unit, because the units cancel in the ratio. Only temperature must be in kelvin.
Why must temperature be in kelvin?
The gas law is a proportion that only works from absolute zero. Using Celsius, a value like 0 °C would wrongly give zero, so you must convert with T = °C + 273 first.
When can I use the simpler gas laws instead?
If one quantity is held constant, use the matching law: Boyle's at constant T, Charles's at constant p, and the pressure law at constant V. The general law handles cases where all three change.

Book a Trial Class

One-hour paid trial · Same-day reply · from RM50/hr

Book a Trial Class

One-hour paid trial · Same-day reply